Source: Manuscript held by G. W. Leibniz Bibliothek, Hanover Shelfmark LBr 355 Bl. 5r Date: 14 July 1703 (?) Translated from the Latin View this translation in PDF format (168k) Back to home page Search texts by keyword(s): (For search strings, just type the words; don't use quotation marks) |
## LEIBNIZ: CASTING OUT ELEVENSAt the end of a letter to Edmond Halley of 14 July 1703, Leibniz wrote: "I am here sending my casting of elevens." ^{1} The following text is Leibniz’s surviving draft of the text he enclosed with that letter.[ LBr 355 Bl. 5r]If this is combined with [casting out] nines, it is more difficult for an error to creep in. It differs from [casting out] nines only in the fact that the latter is done by single digits, while [casting out] elevens is done by pairs of digits counting from right to left. The eleven remainder of each pair is obtained if the left digit is subtracted from the right, increased by 11 if need be. ^{2} Let the remainder of a pair be added to the next pair, and proceed in the same way to the end.^{3}Example: 36945281 has an eleven remainder of 10. For subtracting 8 from 1 + 11 leaves 4. And 5 from 2 + 4 leaves 1. And 9 from 4 + 1 + 11 leaves 7, and 3 from 6 + 7 leaves 10. Or even better: Casting out nines differs from casting out elevens because in the former the digits are joined together as you like, [while] in the latter the digits of the odd positions, counting from right to left, are joined together, and the positions of the even digits are also joined together; from the remainder of the odd [positions], increased by 11 if need be, the remainder of the even [positions] is increased. Example: 36945281 has an elevens remainder of 10. For by casting 11 from 1 + 2 + 4 + 6 there remains 2, and by casting 11 from 8 + 5 + 9 + 3 there remains 3, and by subtracting 3 from 2 + 11, there remains 10. Therefore, the operation can be performed mentally without calculation. NOTES: 1. Correspondence and Papers of Edmond Halley, ed. Eugene Fairfield MacPike (London: Taylor and Francis, 1937), 200.2. That is, increased by 11 if the value of the left digit is greater than that of the right digit. 3. end. │ Many other short-cuts will naturally emerge, but this is the most common and regular way. │ deleted.© Lloyd Strickland 2022 |